1.Substitute 4z +1 for y in the i 3 + 2(4 +1) = 13 3 + 8z + 2 = 13 1Ix = 11 = 1 y —— 4(1) +1 = 5 The solution set is { (1,5)) . 2.Multiply the second equation equation. z + 4y = 142(2)— \ = I —\ = —3 \ = 3 The solution set is { (2,3)) .